Semi urgent - Laplace Transform

**Peleus** · April 27th 2010, 08:41 PM

Hi all,

I'll state the question, then explain my thinking.

Evaluate $\int_0^{\inf} [ H(t - \frac{\pi}{4}) - H(t)] \cos{2t}e^{-st} dt$ where $s > 0$

Ok, I know the heaviside function limits the range between 0 and $\frac{\pi}{4}$ .

I also know that the laplace transform of $\cos{2t}$ is $\frac{s}{s^2 + 4}$

What I don't know is how I'm meant to effectively combine these properties together to correctly evaluate the integral.

Any help would be greatly appreciated.

**maddas** · April 27th 2010, 08:52 PM

Your integral is equal to $\int_0^{\pi/4}- \cos(2t)\,e^{-st} \,\mathrm{d}t$ is it not?

**Peleus** · April 27th 2010, 08:59 PM

I can see how the heaviside function can produce the new limits, however I can't see how you got the negative out the front of the variable and I'm unsure of what to do with it from there.

**Peleus** · April 27th 2010, 09:01 PM

Actually, I think I use this from the table of integrals to produce the answer from the above...

But again I'm unsure how you got that negative out the front.

**maddas** · April 27th 2010, 09:02 PM

What value does $H(t-\pi/4) - H(t)$ have on the interval [0,pi/4]?

From there, use integration by parts I think.

**Peleus** · April 27th 2010, 09:07 PM

Ah ok, -1 obviously. Thanks.

Math Help - Semi urgent - Laplace Transform

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