∫∫∫16x^3 dV
Bounded by the cone and sphere below:
Z = √(x^2 + y^2)
x^2 + y^2 + z^2 = 4
For my bounds of integration I got 0 < phi < pi/3 , 0 < theta < 2pi , and 0 < rho < 4. Is this correct?
∫∫∫16x^3 dV
Bounded by the cone and sphere below:
Z = √(x^2 + y^2)
x^2 + y^2 + z^2 = 4
For my bounds of integration I got 0 < phi < pi/3 , 0 < theta < 2pi , and 0 < rho < 4. Is this correct?