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Math Help - Triple Integral in Spherical Coordinates

  1. #1
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    Triple Integral in Spherical Coordinates

    ∫∫∫16x^3 dV

    Bounded by the cone and sphere below:

    Z = √(x^2 + y^2)

    x^2 + y^2 + z^2 = 4


    For my bounds of integration I got 0 < phi < pi/3 , 0 < theta < 2pi , and 0 < rho < 4. Is this correct?
    Last edited by wizrd54; April 27th 2010 at 06:25 PM.
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  2. #2
    Senior Member Tinyboss's Avatar
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    There are different ways to set up spherical coordinates, but if you use the setup in the Wikipedia article on spherical coordinates, I think you'd want 0\le\theta\le\frac\pi 2, 0\le\phi<2\pi, and 0\le\rho\le4.
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