\sum{(n^.5)\over((n^2) + 1)} Limits n = 1 to infinity I am new to this forum so I don't know if I have written this correctly.
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It converges since $\displaystyle {n^{1/2}\over n^2 + 1} \le {n^{1/2}\over n^2} = {1 \over n^{3/2}}$. I don't know its sum though.
Thanks for that. Just to confirm did you use the comparison test. It is great to have such a good site to go to where you haven't got anywhere else to go. Thank you for the quick reply.
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