sum_(n=-1)^infinity(-1)^(n+1) (1/3)^n = 9/4~~2.25...

How do you prove that? Is there a certain formula to figure out the sum of the alternating series?

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- Apr 26th 2010, 11:01 PMBrothaalternating series
sum_(n=-1)^infinity(-1)^(n+1) (1/3)^n = 9/4~~2.25...

How do you prove that? Is there a certain formula to figure out the sum of the alternating series? - Apr 26th 2010, 11:37 PMChris L T521