1. ## Quick limit question

I'm working on an improper integral problem and have come down to a part I don't quite understand. The solutions manual shows....

$\displaystyle \lim$ $\displaystyle \ln|\frac{b-1}{b+1}|$ = $\displaystyle \ln 1$
The limit is being evaluated as b approaches neg. infinity.

I'm having a hard time seeing how this equates and any help would be much appreciated.

Thanks!

2. Originally Posted by shawnbuck
I'm working on an improper integral problem and have come down to a part I don't quite understand. The solutions manual shows....

$\displaystyle \lim$ $\displaystyle \ln|\frac{b-1}{b+1}|$ = $\displaystyle \ln 1$
The limit is being evaluated as b approaches neg. infinity.

I'm having a hard time seeing how this equates and any help would be much appreciated.

Thanks!
$\displaystyle \frac{b - 1}{b + 1} = \frac{b + 1 - 2}{b + 1}$

$\displaystyle = 1 - \frac{2}{b + 1}$.

What happens as $\displaystyle b \to -\infty$?

3. The second term approaches 0.

Thanks for the help.