just want to make sure i'm doing this problem right, any help is appreciated.
find derivative:
log7x^2-1
= log7 + logx^2-1
= lnx^2-1 / ln7
=ln(x+1)(x-1) / ln7
= 1/ln7 + (1/x+1 * 1/x-1)
??
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just want to make sure i'm doing this problem right, any help is appreciated.
find derivative:
log7x^2-1
= log7 + logx^2-1
= lnx^2-1 / ln7
=ln(x+1)(x-1) / ln7
= 1/ln7 + (1/x+1 * 1/x-1)
??
Please use brackets where they're needed, this is too hard to read.Quote:
Originally Posted by JGaraffa
Is the function
$\displaystyle y = \ln{(7x^2)} - 1$?
Here is the way to find the derivative of log functions;
$\displaystyle \frac{Derivative~of ~inside~of~ log}{inside~ of~ log}$
Is you function $\displaystyle \log(7x^2-1)$?
If yes, from the above rule $\displaystyle \frac{Derivative~of ~7x^2-1}{7x^2-1}=\frac{14x}{7x^2-1}$
ah i knew i forgot brackets somewhere.
the original problem was
log7(x^2-1)
