# Thread: Is there a trick for higher derivatives?

1. ## Is there a trick for higher derivatives?

2. $f(x) = \frac{x^2-2x+4}{x-2}$
$f'(x)= \frac{x(x-4)}{(x-2)^2}$
3. $\frac{x^2-2x+4}{x-2} = \frac{x(x-2)+4}{x-2} = x + \frac{4}{x-2}$, if that helps.