Originally Posted by
bilderback I have no idea how to answer these problems
Solve for x
ln((x-4)^2)=14
$\displaystyle \textcolor{red}{(x-4)^2 = e^{14}}$
solve for x
Find an equation of the tangent line to the graph of the function at the point (1, 1).
1+ln(xy)=e^x
$\displaystyle \textcolor{red}{1 + \ln{x} + \ln{y} = e^x}$
implicit derivative ...
$\displaystyle \textcolor{red}{\frac{1}{x} + \frac{1}{y} \cdot \frac{dy}{dx} = e^x}$
determine the slope at the indicated coordinates, then write the tangent line equation.
Solve the differential equation
dy/dx=(9e^x-2e^-x)^2
$\displaystyle \textcolor{red}{y = \int 81e^{2x} - 36 + 4e^{-2x} \, dx}$
finish it