0.8 = 0.8cos(t) - 1.2sin(2t) How would I solve this?
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Originally Posted by kmjt 0.8 = 0.8cos(t) - 1.2sin(2t) How would I solve this? This is trig, not calculus. Either way you should use the identity $\displaystyle \sin(2t) = 2\sin(t) \cos(t)$ $\displaystyle 2.4 \sin(t) \cos(t) - 0.8\cos(t) + 0.8 = 0$ This will factor
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