# Math Help - formula rearranged

1. ## formula rearranged

Hi,

I was just wondering if someone could put me in the right direction with rearranging this, from the LHS to the RHS equation?

ieit = i
eit – 1 1- e-it

2. Originally Posted by Karty
Hi,

I was just wondering if someone could put me in the right direction with rearranging this, from the LHS to the RHS equation?

ieit = i
eit – 1 1- e-it
3. Do you mean $\frac{ie^{it}}{e^{it}-1}= \frac{i}{1- e^{-it}}$?
If so, multiply both numerator and denominator by $e^{-it}$.