Try substituting x^2 + 3 instead
u = x^2 + 3
du = 2x dx
du/2 = x dx
so the resulting integral will be sqrt(u)/2
So I have a square root integral as follows...
x*sqrt((x^2) + 3)dx
Do I take the u-sub of this thing?
u = x^2
du = 2xdx
xdx = du/2
and what do I do from there?
I know that it will be sqrt(u + 3)du/2
but that doesnt help me much...
Well I should say
The equation actually is...
in terms of rdrd(theta)
and I seperated theta and r out into seperate integrals
I have r*sqrt((r^2) - (a^2))dr
the equation was originally derived from the equation of a sphere...
z^2 = x^2 + y^2 - a^2
and a is some arbitrary radius.