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Math Help - partial diff.

  1. #1
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    Post partial diff.

    Hey All,

    how would you solve the following:

    given that = 3x^2 + y^3 + z^4

    show that x/2.∂/∂x + y/3.∂/∂y + z/4.∂/∂z =


    I have found; ∂/∂x=6x, ∂/∂y=3y^2, ∂/∂z=4z^3
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  2. #2
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    Hello, dadon!

    You're that close . . .


    Given: .F .= .3x + y + z^4 .[1]

    show that: .(x/2)(∂F/∂x) + (y/3)(∂F/∂y) + (z/4)(∂F/∂z) .= .F .[2]


    I have found: .∂F/∂x = 6x, .∂F/∂y = 3y, .∂F/∂z = 4z

    Substitute your findings into the left side of [2]:

    . . (x/2)(6x) + (y/3)(3y) + (z/4)(4x)

    . . = .3x + y + z^
    4
    . . . . \___________/ . . . . . Q.E.D.
    . . . .
    From [1], this is F

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  3. #3
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    Post

    Thanks Soroban lol.. that was doing my head in this morning..
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