http://i43.tinypic.com/2ekj2n8.jpg

find the second derivative (0)

I get two different answer, one where i expand the brackets out, and one where i just make 1-q = p

- Apr 24th 2010, 08:57 AMadam_leedsIm having trouble finding the second derivative of this equation
http://i43.tinypic.com/2ekj2n8.jpg

find the second derivative (0)

I get two different answer, one where i expand the brackets out, and one where i just make 1-q = p - Apr 24th 2010, 09:24 AMRuun
$\displaystyle \left( \frac{1}{f} \right) ' = - \left( \frac{f'}{f^2} \right) $

Let $\displaystyle f = 1 - qe^{it}$ - Apr 24th 2010, 12:21 PMHallsofIvy
What reason would you have for setting 1- q= p?

- Apr 25th 2010, 01:34 AMadam_leeds