I need to find the area of the region bounded by the graph of y= x^3 - 2x^2 - 3x, and the x- axis.
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Originally Posted by lucky13 I need to find the area of the region bounded by the graph of y= x^3 - 2x^2 - 3x, and the x- axis. Solving when $\displaystyle y=0 \implies 0= x^3 - 2x^2 - 3x \implies 0= x(x^2 - 2x - 3) $ $\displaystyle \implies 0= x(x-3)(x+1) \implies x= -1,0,3 $ Now solve $\displaystyle \int_{-1}^0x^3 - 2x^2 - 3x~dx - \int_{0}^3x^3 - 2x^2 - 3x~dx $
Do I replace x with -1 in the first formula and x with 3 in the second and then subtract the two?
Integrate first, what do you get?
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