Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL) do i just take the integral of the top minus the bottom?
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Originally Posted by -DQ- Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL) do i just take the integral of the top minus the bottom? Not yet, you need to find out if they intersect on the given interval first. Do they? i.e. solve $\displaystyle \sin 2x = \cos x$
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