Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL)

do i just take the integral of the top minus the bottom?

Printable View

- Apr 22nd 2010, 08:38 PM-DQ-Area of enclosed region
Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL)

do i just take the integral of the top minus the bottom? - Apr 22nd 2010, 08:56 PMpickslides