# Area of enclosed region

• April 22nd 2010, 07:38 PM
-DQ-
Area of enclosed region
Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL)

do i just take the integral of the top minus the bottom?
• April 22nd 2010, 07:56 PM
pickslides
Quote:

Originally Posted by -DQ-
Find the area of the region enclosed by y=sin2x and y=cosx for -pi/2 < x < pi/6? (INCLUSIVE INTERVAL)

do i just take the integral of the top minus the bottom?

Not yet, you need to find out if they intersect on the given interval first.

Do they? i.e. solve $\sin 2x = \cos x$