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Math Help - derivative of LN?

  1. #1
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    derivative of LN?

    i'm not quite sure how to deal with this problem considering it as to LN's in it anyone care to explain how this should be worked?

    y = ln(lnx²)

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  2. #2
    Newbie Riyzar's Avatar
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    You have a function inside of a function inside of a function, so the chain rule would work well here.
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  3. #3
    Senior Member
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    y=\ln(\ln(x^2))

    Notice that:

    \left[ \ln u \right]' = \frac{1}{u} \cdot u'

    So:

    y'=\frac{1}{\ln(x^2)} \cdot \left[ \ln(x^2) \right]' = \frac{1}{\ln(x^2)} \cdot \frac{1}{x^2} \cdot \left[ x^2 \right]' = \cdots
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