1. ## derivative of LN?

i'm not quite sure how to deal with this problem considering it as to LN's in it anyone care to explain how this should be worked?

y = ln(lnx²)

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2. You have a function inside of a function inside of a function, so the chain rule would work well here.

3. $y=\ln(\ln(x^2))$

Notice that:

$\left[ \ln u \right]' = \frac{1}{u} \cdot u'$

So:

$y'=\frac{1}{\ln(x^2)} \cdot \left[ \ln(x^2) \right]' = \frac{1}{\ln(x^2)} \cdot \frac{1}{x^2} \cdot \left[ x^2 \right]' = \cdots$