i'm not quite sure how to deal with this problem considering it as to LN's in it anyone care to explain how this should be worked?
y = ln(lnx²)
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$\displaystyle y=\ln(\ln(x^2))$
Notice that:
$\displaystyle \left[ \ln u \right]' = \frac{1}{u} \cdot u'$
So:
$\displaystyle y'=\frac{1}{\ln(x^2)} \cdot \left[ \ln(x^2) \right]' = \frac{1}{\ln(x^2)} \cdot \frac{1}{x^2} \cdot \left[ x^2 \right]' = \cdots$