1. f(x) = (2x-1)^5 (x+1)

What is the equation of the tangent line at x=1?

a. y=21x+2

b. y=21x-19

c. y=11x-9

d. y=10x+2

e. y=10x-8

2. f ' (x) = 2x+1 f(1) = 4

Approximate f(1.2) using line tangent to the graph at x=1

a. 0.6

b. 3.4

c. 4.2

d. 4.6

e. 4.64

I appreciate any help.

Thanks.