Thread: Displacement Problem

An object moves along a line. At time t=0, the position of the object is -1 and the velocity at this time is 2. If the acceleration of the object is a(t) = √2t+1, find out where the object is at time t = 4. ( The acceleration is all under the square root)!

Originally Posted by cole123

An object moves along a line. At time t=0, the position of the object is -1 and the velocity at this time is 2. If the acceleration of the object is a(t) = √2t+1, find out where the object is at time t = 4. ( The acceleration is all under the square root)!

Solve subject to x(0) = -1 and v(0) = x'(0) = 2.

Then evaluate x(4).

If you need more help, please show what work you've done and say where you are stuck.

Right now I have 1/3 (2t+1) ^(3/2) + 5/3

I used 1/2 [int] u^(1/2) du
then solved for C and got 5/3

Fine - that's the velocity function. Integrate that to get position.