Find the Laurent series representation of $\displaystyle \frac{e^z}{(z+1)^2}$ for $\displaystyle (0<\left |z+1 \right |< \infty)$.
I really don't understand the process of getting the series representation.
First get the Taylor's series for $\displaystyle e^z$ about the point z= -1. Can you do that?
(The Taylor's series for f(z) about z= a is $\displaystyle \sum_{n=0}^\infty \frac{f^{(n)}(a)}{a!}(z- a)^n$ where $\displaystyle f^{(n)}$ indicates the nth derivative. It should be easy to find the nth derivative of $\displaystyle e^z$ at z= -1.
Then divide each term by $\displaystyle (z+ 1)^2$