1. ## Lagrange error problem

you wish to estimate $e^x$, over the interval |x|< 2, with an error less than 0.001. The Lagrange error term suggests that you use a Taylor polynomial at 0 with at least

(A) 6
(B) 9
(C) 10
(D) 11
(E) 12

2. You can evaluate
$\frac {x^n}{n!}<10^{-3}$

$x=2$

$\frac {2^n}{n!} < 10^{-3}$

3. Originally Posted by zzzoak
You can evaluate
$\frac {x^n}{n!}<10^{-3}$

$x=2$

$\frac {2^n}{n!} < 10^{-3}$
thanks your method for lagrange error is simpler than what i learned in calc class