Volume of revolution

**bhuang** · April 21st 2010, 01:06 PM

The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!

**skeeter** · April 21st 2010, 01:39 PM

Originally Posted by bhuang

The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!

$V = \pi \int_0^1 \sin^2(2x) \, dx \approx 1.87$

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