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Math Help - Volume of revolution

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    Volume of revolution

    The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

    I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!
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    Quote Originally Posted by bhuang View Post
    The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

    I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!
    V = \pi \int_0^1 \sin^2(2x) \, dx \approx 1.87
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