# Volume of revolution

• Apr 21st 2010, 02:06 PM
bhuang
Volume of revolution
The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!
• Apr 21st 2010, 02:39 PM
skeeter
Quote:

Originally Posted by bhuang
The area between the curve y=sin2x, the x-axis between 0 and 1 and the line x=1 is rotated through 360 degrees about the x-axis. Find the volume.

I found the volume by multiplying pi to the integral between the lower and upper limit of 0 and 1, respectively. My answer is 1.87. Can someone find the volume and tell me what they get? Thanks!

$V = \pi \int_0^1 \sin^2(2x) \, dx \approx 1.87$