Let f(x) = |x^2 - 1 | x is an element of [0,2]

a) find were f is strictly increasing and where it is strictly decreasing

b) find the maximum and minimum of f on [0,2]

Results 1 to 2 of 2

- April 22nd 2007, 04:56 PM #1

- Joined
- Feb 2007
- Posts
- 23

- April 22nd 2007, 06:19 PM #2

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 10

The function f(x)=|x^2-1| on [0,2] is continous and has a maximum and minimum.

Find the critical points, i.e. where the derivative does not exists or is zero. The place where the derivative does not exist can only occur at x^2-1=0 that is x=1 on [0,2]. I leave it to thee to show the function is not differenciable there.

Next find the derivative of f(x). To do that use the following theorem.

**Theorem:**Let f(x)=|x| then if x!=0 the function is differenciable and the derivative is sgn(x). Here.

Thus, the derivative of f(x)=|x^2-1| on (0,2) and x!=1 is:

2x*sgn(x^2-1)

We need that,

2x*sgn(x^2-1)=0

Since sgn(x^2-1)!=0 for x!=0 we must have,

2x=0.

Which has no solutions on (0,2).

Thus, the only critical point is the non-differenciable point we found before x=1.

Compare values with x=0 and x=2. To find maximum and minimum.