I worked it down to

and then

x = 5

a= 1

x = -1

-12 = b

whats confusing me is that if i let x = -1 for c i would get -12 = C0 which is -12 = 0

is my equation wrong?

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- Apr 21st 2010, 05:16 AMx5pyd3rxPartial Fraction

I worked it down to

and then

x = 5

a= 1

x = -1

-12 = b

whats confusing me is that if i let x = -1 for c i would get -12 = C0 which is -12 = 0

is my equation wrong? - Apr 21st 2010, 06:13 AMDeadstar
Never thought about doing the question like that but lets roll with it...

If x=5, everything bu the A term is 0 so we get...

216A = 216.

So A = 1.

If x=-1, everything but the D term cancels and you get...

-6D = -12, D = 2

Now set x to be something generic like 0.

Chances are you'll get something like ...B + ...C = -9

Then set x to be something else. Like 1 for example.

Once again you'll get an equation involving B and C.

Solve for B and C using simultaneous equations. - Apr 21st 2010, 06:16 AMDeadstar
Alternatively you could see that you'll get Ax^3 + ... + Bx^3 + ...

So B must be equal to 0.

Something tells me that won't work though. You sure that equation is going to work..? - Apr 21st 2010, 06:18 AMDeadstar
Actually yeah it will be. C=0 as well.