limits root 3 and 1

Please show me how to do this.

Thanks[/quote]

x = tanθ

Then dx = sec^2(θ)*d(θ)

When x = 1, θ = Π/4

When x = sqrt(3), θ = π/3

The given integration becomes

int[(1-tan^2θ)/(1+tan^2θ)*sec^2(θ)*d(θ)

That reduces to

int[(1-tan^2(θ)*d(θ) between π/4 to π/3.

Put tan^2(θ) = sec^2(θ) - 1 and solve the integration.