f(t) = sin2(t)----This is sin squared t, 0 ≤ t ≤ π
Determine the interval(s) on which the function is concave up.
Determine the interval(s) on which the function is concave down.
Determine the inflection Points
Determine the critical points.
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f(t) = sin2(t)----This is sin squared t, 0 ≤ t ≤ π
Determine the interval(s) on which the function is concave up.
Determine the interval(s) on which the function is concave down.
Determine the inflection Points
Determine the critical points.
f'(t) = 2sin(t)cos(t)Quote:
Originally Posted by elexis10
For concave up function, the slope is positive.
In the first quadrant both sin(t) and cos(t) are positive.
For concave down function, the slope is negative.
It is possible when t is .........?