Find all numbers c that satisfy the conclusion of the Mean Value Theorem.
so f(x)=e ^ -2x [0,3]
using f(b)-f(a)=f'(c)(b-a)
so that's
f'(x) = 2e^-2x
e^-2(3)-e^-2(0) = 2e^-2x(3-0)
e^-6-1=3e^-2x
now how do i solve for x?
the ^ means exponent,
the latex tags won't turn it into an exponent, how weird...