Find all numbers c that satisfy the conclusion of the Mean Value Theorem.

so f(x)=e ^ -2x [0,3]

using f(b)-f(a)=f'(c)(b-a)

so that's

f'(x) = 2e^-2x

e^-2(3)-e^-2(0) = 2e^-2x(3-0)

e^-6-1=3e^-2x

now how do i solve for x?

the ^ means exponent,

the latex tags won't turn it into an exponent, how weird...