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Math Help - find limit of s(n) as n approachs infinity.

  1. #1
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    find limit of s(n) as n approachs infinity.

    s(n) = (6/n^5) * [((n^3)*(n+1)^4)/7)]

    Can someone please explain to me why the answer of this is unbounded and not 6/7 ?!?!
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  2. #2
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    Quote Originally Posted by action812 View Post
    s(n) = (6/n^5) * [((n^3)*(n+1)^4)/7)]

    Can someone please explain to me why the answer of this is unbounded and not 6/7 ?!?!
    degree of n in the numerator is 7

    degree of n in the denominator is 5

    effectively, s(n) is of the order of n^2
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