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Math Help - Partial Fraction.

  1. #1
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    Partial Fraction.

    \frac{6x^2 - 4x - 20}{x(x-4)(x+1)}dx

    I have no clue how to proceed from here. everything i try dosent look right.
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  2. #2
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by x5pyd3rx View Post
    \frac{6x^2 - 4x - 20}{x(x-4)(x+1)}dx

    I have no clue how to proceed from here. everything i try dosent look right.
    Before starting integration, use partial fractions to decompose your term>

    \frac{6x^2 - 4x - 20}{x(x-4)(x+1)} = \frac{A}{x} + \frac{B}{x-4} + \frac{C}{x+1}.....................(1)

    or,

    {6x^2 - 4x - 20}= A(x-4)(x+1) + B (x)(x+1)  + C (x)(x-4)


    find out A, B, and C. Plug them in equation (1) and then integrate!
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