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Thread: integrals

  1. #1
    Super Member
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    Aug 2009
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    integrals

    find the area of the portion of the sphere z=(1-x^2-y^2)^(1/2) which lies between z=0 and z=1?

    my working:

    that would be the double integral dS where dS is the area element of S.
    i tried to parametrise it then from
    double integral dS to integrate from r=0 to 1 then integrate from phi = 0 to pi drdphi...

    may i know what is wrong with my working?

    thanks!
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  2. #2
    Newbie
    Joined
    Apr 2010
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    There is no dr here since radius of sphere does not change. The easiest way is to move to spherical coordinates. You integrate with respect to Pi and theta.
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