Thread: Concave up concave down

Need to find the intervals in which the equation is concave up as well as concave down, the pionts of inflection and critical points

heres the equation

f(t) = sin2(t) 0 ≤ t ≤ π

Thanks

Originally Posted by elexis10

Need to find the intervals in which the equation is concave up as well as concave down, the pionts of inflection and critical points

heres the equation

f(t) = sin2(t) 0 ≤ t ≤ π

Thanks

Did you mean or ?

This is a pretty straightforward application of definitions, you'll need to find the first and second derivatives and set them to zero, then divide the interval [0, π] accordingly.

i meant sin squared t