# Concave up concave down

• April 20th 2010, 07:38 AM
elexis10
Concave up concave down
Need to find the intervals in which the equation is concave up as well as concave down, the pionts of inflection and critical points

heres the equation

f(t) = sin2(t) 0 ≤ tπ

Thanks
• April 20th 2010, 07:56 AM
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Quote:

Originally Posted by elexis10
Need to find the intervals in which the equation is concave up as well as concave down, the pionts of inflection and critical points

heres the equation

f(t) = sin2(t) 0 ≤ tπ

Thanks

Did you mean $sin^2(t)$ or $sin(2t)$?

This is a pretty straightforward application of definitions, you'll need to find the first and second derivatives and set them to zero, then divide the interval [0, π] accordingly.
• April 20th 2010, 10:25 AM
elexis10
i meant sin squared t