find the area of the region whose boundaries are given

In the first quadrant, bounded below by the x-axis and above by the curves of y=sin(x) and y=cos(x).

(A) $\displaystyle 2-\sqrt{2}$

(B) $\displaystyle 2+\sqrt{2}$

(C) 2

(D) $\displaystyle \sqrt{2}$

(E) $\displaystyle 2\sqrt{2}$

This is what i did.

$\displaystyle \int_0^{\pi/4} cosx-sinx dx$

solve integral i get: $\displaystyle -1+\sqrt{2}$

which is not one of the multiple choice options above. I think I am not understanding what the question is asking.