Evaluate the definite integral.
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Try a substitution $\displaystyle u=\ln x \implies \frac{du}{dx} = \frac{1}{x} $
Originally Posted by pickslides Try a substitution $\displaystyle u=\ln x \implies \frac{du}{dx} = \frac{1}{x} $ ok so what do I do with the 1/x ?
Originally Posted by tbenne3 ok so what do I do with the 1/x ? Re-write the integral in light of these substitutions.
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