See attachment.

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- April 19th 2010, 03:48 PMWartonMortonimproper integral involving e
See attachment.

- April 19th 2010, 03:51 PMpickslides
You can find using integration by parts.

Do you know this method? - April 19th 2010, 04:10 PMWartonMorton
- April 19th 2010, 04:16 PMpickslides
- April 19th 2010, 04:17 PMWartonMorton
so thus the improper integral is -1 ?

- April 19th 2010, 04:19 PMpickslides
That's what I get.