See attachment.

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- Apr 19th 2010, 04:48 PMWartonMortonimproper integral involving e
See attachment.

- Apr 19th 2010, 04:51 PMpickslides
You can find using integration by parts.

Do you know this method? - Apr 19th 2010, 05:10 PMWartonMorton
- Apr 19th 2010, 05:16 PMpickslides
- Apr 19th 2010, 05:17 PMWartonMorton
so thus the improper integral is -1 ?

- Apr 19th 2010, 05:19 PMpickslides
That's what I get.