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Math Help - improper integral help

  1. #1
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    improper integral help

    Please see attachment. thanks.
    Attached Thumbnails Attached Thumbnails improper integral help-derv.jpg  
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  2. #2
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    Joined
    Feb 2010
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    integrate by letting u = ln(x) du=1/x

    so integral(1/u^2) aka integral(u^-2)

    solved as -1/u resubstituting -1/(lnx)

    -1/(ln(infinity)) - -1/(ln(e))

    the left side approaches 0 and the right side approaches -1 so 0-(-1) means the limit should converge to 1
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