Thread: improper integral help

Please see attachment. thanks.

integrate by letting u = ln(x) du=1/x

so integral(1/u^2) aka integral(u^-2)

solved as -1/u resubstituting -1/(lnx)

-1/(ln(infinity)) - -1/(ln(e))

the left side approaches 0 and the right side approaches -1 so 0-(-1) means the limit should converge to 1