5= 3lnx - 1/2lnx

I assume you have to get both sides of the equation with the same term first. If I multiply by lnx, wouldn't it cancel out on the right side? The same for if I divide?

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- Apr 22nd 2007, 04:05 AMstartingoverlogarithic
5= 3lnx - 1/2lnx

I assume you have to get both sides of the equation with the same term first. If I multiply by lnx, wouldn't it cancel out on the right side? The same for if I divide? - Apr 22nd 2007, 04:27 AMtopsquark
- Apr 22nd 2007, 04:49 AMSoroban
Hello, startingover!

Dan is absolutely correct.

Quote:

5 .= .3·ln(x) - ½·ln(x)

We have: .3·ln(x) - ½·ln(x) .= .5

Combine: . . . . .(5/2)·ln(x) .= .5

Multiply by 2/5: . . . . ln(x) .= .2

Therefore: . . . . . . . . . . x .= .e²