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Math Help - definite integral

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    definite integral

    Evaluate


    Definite Integral = _______
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  2. #2
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    regular substitution u=x^2....du=2x dx

    integral(.5cos(u)) should be easy
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  3. #3
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    Quote Originally Posted by tbenne3 View Post
    Evaluate


    Definite Integral = _______
    use the method of substitution ...

    let u = x^2

    du = 2x \, dx

    \frac{1}{2} \int_0^{\sqrt{\pi}} 2x \cos(x^2) \, dx

    substitute, reset the limits of integration, integrate and evaluate ...
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