1. ## Sequence

Not sure if how i got to the answer is right
the question is... is this sequence strictly increasing or strictly decreasing
$\frac{5^{n}}{2^{n^2}}$sequence with n=1 to infinity
used $A_{n+1}-A_{n}$
which gave me $\frac{5^{n+1}}{2^{(n+1)^{2}}}*\frac{2^{n^2}}{5^n}$
Does simplifying that give me
$\frac{5}{2^{2n+1}}$which is<1; for n is greater than or equal to 1
so the sequence is decreasing

2. Originally Posted by vinson24
Not sure if how i got to the answer is right
the question is... is this sequence strictly increasing or strictly decreasing
$\frac{5^{n}}{2^{n^2}}$sequence with n=1 to infinity
used $A_{n+1}-A_{n}$
which gave me $\frac{5^{n+1}}{2^{(n+1)^{2}}}*\frac{2^{n^2}}{5^n}$

You must have meant that you put $A_n:=\frac{5^n}{2^{n^2}}$ , and then you did $\frac{A_{n+1}}{A_n}$ , not $A_{n+1}-A_n$ ...

Does simplifying that give me
$\frac{5}{2^{2n+1}}$which is<1; for n is greater than or equal to 1
so the sequence is decreasing

Indeed.

Tonio

3. oops sorry about that thanks