How do you find the antiderivative of 1/sin^2(x) or same as sin^-2(x) Thanks
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Originally Posted by shiiganB How do you find the antiderivative of 1/sin^2(x) or same as sin^-2(x) Thanks $\displaystyle (\sin(x))^n = \sin^n (x)$ is only for positive integers of x so your second expression is wrong. $\displaystyle \int \csc^2(x) \, dx$ Which is a standard integral
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