Sigma from k=1 to infinity of (-1)^k+1(4^k)(9^1-k) How do I deal with that (-1)^k+1?
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Originally Posted by Simon777 Sigma from k=1 to infinity of (-1)^k+1(4^k)(9^1-k) How do I deal with that (-1)^k+1?
Originally Posted by Simon777 Sigma from k=1 to infinity of (-1)^k+1(4^k)(9^1-k) How do I deal with that (-1)^k+1? If the series is , then all you have to do is remember that (sum of an infinite convergent geometric series) Tonio
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