Originally Posted by
jstout64 Find te volume of the solid in the first octant of XYZ space bounded below by the coordinate axes and the unit circle, and bounded above by z = 8xy.
So i want the double integral of 8xy dy dx.
The outer integral should be simple, x goes from 0 to 1.
The inner integral though we need to solve for y. y^2 + x^2 = 1.
So y = + or - sqrt(1 - x^2) I only want the positive root.
But since its in the first octant should it be sqrt(1-x^2)/2? because i only want the quarter circle... So my limits for y should be 0 to sqrt(1-x^2)/2.
Do i need to divide by 2?