Originally Posted by
orendacl confirm is this one divergent?
inf x!
sum ------------------------
x=1 1 * 3 * 5 ... ( 2 x -1)
I said that we should start by replacing all n with n+1
Then we multiply an+1 by the reciprocal of an
That leads me to a messy fraction.
I get all messed up with a fraction that looks like:
(x+1)(2x-1)
-----------
2x+1
I come up with the series is divergent but due to abs value of ratio an+1 to an.
How do you solve this so the fraction obtained after the reciprocal is one that is easily taken a limit of to determine divergence or convergence?