given that ∫15x^2 dx = 3430, and x=a and x=-a. Find the value of the constant a.
I'm not quite sure how to approach solving for a.
I(x) = 5x^3
So would I set that equal to 3430?
5x^3=5430
x^3=686
x= approx. 8.8?
The answer is that a=7.
7^3 is 343 ...
3430/10 = 343 .. but how could I get to that (justify it anyways)
Thanks so much, I really want to understand how to do this, I'm just confused on where to go from here.
Thanks!