y=x^3.

P = (3,27)

PQ is tangent to the curve at P

Picture of graph: http://i42.tinypic.com/fvl8gy.jpg

Find the area of the region enclosed between the curve, PQ and the x-axis.

I(x) = (1/4)x^4

I can see that x=0 at the origin...

I(0) = (1/4)(0)^4 = 0

How can I find point Q? It's tangent to the curve at point P...but I'm not sure how to find it :[

The area is 6.75..so how do I arrive at that? How can I find point Q? Thanks!