P = (3,27)
PQ is tangent to the curve at P
Picture of graph: http://i42.tinypic.com/fvl8gy.jpg
Find the area of the region enclosed between the curve, PQ and the x-axis.
I(x) = (1/4)x^4
I can see that x=0 at the origin...
I(0) = (1/4)(0)^4 = 0
How can I find point Q? It's tangent to the curve at point P...but I'm not sure how to find it :[
The area is 6.75..so how do I arrive at that? How can I find point Q? Thanks!