$\displaystyle \lim_{x \to 0}\frac{arcsin x - x}{x^3}$ I use L'Hospitals rule.. but i keep getting stuck over and over. the correct answer is $\displaystyle \frac{1}{6}$.. but how...
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Originally Posted by eddie2042 $\displaystyle \lim_{x \to 0}\frac{arcsin x - x}{x^3}$ I use L'Hospitals rule.. but i keep getting stuck over and over. the correct answer is $\displaystyle \frac{1}{6}$.. but how... never mind.. i've solved it :P
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