Let C be a circle in the y-z plane (y-3)^2 + z^2 = 1. If C is revolved around the z-axis, the resulting surface is a torus ( a doughnut shape). What is the equation of this surface?
A) x^2 + y^2 + z^2 = 6y
B) (x^2 + y^2 + z^2)^2 = 8 + 36(x^2 + z^2)
C) (x^2 + y^2 + z^2 + 8)^2 = 36(x^2 + z^2)
D) (x^2 + y^2 + z^2 + 8)^2 = 36(x^2 + y^2)
E) (x^2 + y^2 + z^2 + 8)^2 = 36(y^2 + z^2)
I am actually not sure how to do this at all. Can anyone help me to start to do this