Find the volume of the solid in the first octant of xyz space, bounded below by the coordinate axes and the unit circle, and bounded above by z = 8xy.
The unit circle would be x^2 + y^2 = 1.
I know volume will be the double integral of 8xy.
But I am having trouble setting up the limits of integration.
Would the inner integral be from y = -sqrt(x^2 + y^2) to y = sqrt(x^2 + y^2)? then the outer one from 0 to 1 since we in the first octant?
I am not liking the square root so i might be need polar i am not sure....